Questions¶
Difficulty: Easy
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
Coding¶
python¶
# -*- coding: utf-8 -*-
class Solution(object):
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
if s is None or len(s) == 0:
return 0
else:
count, i = 0, len(s) - 1
while i >= 0 and s[i] == " ":
i -= 1
while i >= 0 and s[i] != " ":
count += 1
i -= 1
return count